WebClick here👆to get an answer to your question ️ 1 : 10 Different books are to be arranged on a shelf. Find the number of ways in which this can be done, if two specified books are (1) always together (i) never together Solution : ) The number of ways in which, two specified books are always together = 2 x(10 - 1)! = 2 x 9! = 725760. (ii) The number of ways in … Web14 okt. 2024 · In how many ways can 11 books on English and 9 books on French be placed in a row on a shelf so that two books on French may not be together? in-how-many-ways-can-11-books-on-english-and-9-books-on-87352.html#p1394032 Your solution was : I would offer different solution. We have 11 English and 9 French books, …
How many ways can 9 books be arranged on a shelf so that 5 of the books ...
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There are 5 different French books and 5 different Spanish
WebWays , because 4+5+5 different books will be there So, 14! = 14*13*12*11*10*9 … View the full answer Transcribed image text: 11. [-14 Points] DETAILS MY NOTES A bookshelf contains 4 different mathematics textbooks, 5 different engineering textbooks, and 5 different history textbooks. Web17 aug. 2024 · First we take books of a particular subject as one unit. Thus there are 4 units which can be arranged in 4! = 24 ways. Now in each of arrangements, mathematics books can be arranged in 3! ways, history books in 4! ways, chemistry books in 3! ways and biology books in 2! ways. Thus the total number of ways = 4! × 3! × 4! × 3! × 2! = … WebAlgebra. Question. a) How many ways are there of arranging three different mathematics books, five different history books, and four different French books side by side on a shelf if books of the same subject must be together. b) How many arrangements of these books are possible if a mathematics book must be on each end and the French books … high hopes ava reed